-8t^2+5t+1=0

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Solution for -8t^2+5t+1=0 equation:



-8t^2+5t+1=0
a = -8; b = 5; c = +1;
Δ = b2-4ac
Δ = 52-4·(-8)·1
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{57}}{2*-8}=\frac{-5-\sqrt{57}}{-16} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{57}}{2*-8}=\frac{-5+\sqrt{57}}{-16} $

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